780=2x^2+4x-32

Solution for 780=2x^2+4x-32 equation:

780=2x^2+4x-32

We move all terms to the left:

780-(2x^2+4x-32)=0

We get rid of parentheses

-2x^2-4x+32+780=0

We add all the numbers together, and all the variables

-2x^2-4x+812=0

a = -2; b = -4; c = +812;
Δ = b2-4ac
Δ = -42-4·(-2)·812
Δ = 6512
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6512}=\sqrt{16*407}=\sqrt{16}*\sqrt{407}=4\sqrt{407}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{407}}{2*-2}=\frac{4-4\sqrt{407}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{407}}{2*-2}=\frac{4+4\sqrt{407}}{-4}
$